MapleCTF2022

给定了p^4-q^3=hint,p*q=n直接解方程就可以了#sagefromCrypto.Util.numberimport*N=e=enc=hint=#p=var('p')#eq =p^4-hint-N^3/p^3==0#solve=solve(eq,p)#print(solve)p=11917573148183173444338385104784582231114229409447...